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memblock: mark bytes preceding an aligned allocation as reserved.

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this prevents tiny holes of free memory appearing between
blocks of aligned allocations.
This commit is contained in:
max 🍓
2023-02-07 15:57:18 +00:00
parent e9d4b60181
commit 51ad3d48fd
1 changed files with 11 additions and 5 deletions
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16
vm/memblock.c
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@@ -235,21 +235,27 @@ static phys_addr_t do_alloc(size_t size, phys_addr_t align)
align = 0x8;
}
/* the base address of the memory region to reserved */
phys_addr_t allocated_base = ADDR_MAX;
/* the address to return to the caller. may be different from
allocated_base depending on alignment requirements. */
phys_addr_t returned_base = ADDR_MAX;
phys_addr_t region_start = memblock.m_alloc_start - memblock.m_voffset;
phys_addr_t region_end = memblock.m_alloc_end - memblock.m_voffset;
memblock_iter_t it;
for_each_free_mem_range (&it, region_start, region_end) {
if (it.it_base & (align - 1)) {
it.it_base &= ~(align - 1);
it.it_base += align;
phys_addr_t base = it.it_base;
if (base & (align - 1)) {
base &= ~(align - 1);
base += align;
}
size_t region_size = it.it_limit - it.it_base + 1;
size_t region_size = it.it_limit - base + 1;
if (region_size >= size) {
allocated_base = it.it_base;
returned_base = base;
break;
}
}
@@ -263,7 +269,7 @@ static phys_addr_t do_alloc(size_t size, phys_addr_t align)
return 0;
}
return allocated_base;
return returned_base;
}
void *memblock_alloc(size_t size, phys_addr_t align)